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8v^2-18v+7=0
a = 8; b = -18; c = +7;
Δ = b2-4ac
Δ = -182-4·8·7
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10}{2*8}=\frac{8}{16} =1/2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10}{2*8}=\frac{28}{16} =1+3/4 $
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